and we get to two new things: public string Name and public int Integer. Ok, so we see the constructors, nothing new there. So, if I want to convert an integer to a string, I use the very helpful (and near-universal) method.
One of the best things in C# is the fact that they make casting pretty easy: there are a lot of methods out there to do casting, besides doing the () thing. You need to just access a single character in the string rather than try to convert the entire thing into a single character. You also can't cast a string to a character- a string, if you recall, is an array of characters. If you make a mistake and try to do something like int i = (int)IMyBeaconVariable the compiler will helpfully say, "Hey, you know this isn't going to work, right?" in its own, cold way. I can't cast a IMyBeacon to an int- they are inherently incompatible, since IMyBeacon is a class and is far too complex to be boiled down to an integer. Not everything is castable to something else. You do have to make sure that what you are casting is compatible, however. The best way to summarize casting: Casting is the act of telling the system that yes, I really did mean to do that, and no, you don't need to tell me that these two variables aren't the same type, thank you. Note: The example I used is definitely not an optimal solution, but this is about casting and not how to overload a method, which comes later, when I talk about methods. 0 being there and would return an error saying, "hey, you know this isn't an int you are saving to an int, right?") Semantics, really, but the computer cares about the.
Then the result, which is returned as a double (so in this case, it would come back as 2.0) is cast into an int (now it becomes 2. So what did I do there? I made a single method (DivideTwoNumbers) and asked it to take two var variables (remember, var is context-sensitive- it automatically types the variable as to what is assigned to it), then divide one into the other, while converting the second number explicitly into a double (casting the variable as a double, basically). Public double DivideTwoNumbers(var i, var j)
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